CVE-2026-90124

Published Sep 17, 2026

Description

In the Linux kernel, the following vulnerability has been resolved: irqchip/renesas-rzg2l: Fix loss of interrupt rzg2l_clear_irq_int() and rzg2l_clear_tint_int() perform a read-modify-write on the ISCR/TSCR status registers to clear the bit for the interrupt just handled. Since these registers are write-0-to-clear per bit, this is racy: If another interrupt's status bit gets set between the read and the write, that bit is written back as 0 by the software-constructed value, clearing an interrupt that hasn't been serviced yet and losing it. This can be reproduced by triggering multiple interrupts at once, e.g.: gpioset -c gpiochip0 355=0 353=0 328=0 352=0 Fix this by writing back only the bit being cleared, with all other bits set to 1, instead of read-modify-writing the whole register. Since 1-bits are left unchanged by hardware, concurrently-set status bits for other interrupts are preserved.

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EPSS — Exploit Prediction

0.0021
Probability of exploitation
0.10%
Percentile rank

EPSS estimates the probability that this vulnerability will be exploited in the wild within the next 30 days. A higher score means more likely to be exploited.

References

Frequently Asked Questions

What is CVE-2026-90124? +
In the Linux kernel, the following vulnerability has been resolved: irqchip/renesas-rzg2l: Fix loss of interrupt rzg2l_clear_irq_int() and rzg2l_clear_tint_int() perform a read-modify-write on the ISCR/TSCR status registers to clear the bit for the interrupt just handled. Since these registers are write-0-to-clear per bit, this is racy: If another interrupt's status bit gets set between the read and the write, that bit is written back as 0 by the software-constructed value, clearing an interrupt that hasn't been serviced yet and losing it. This can be reproduced by triggering multiple interrupts at once, e.g.: gpioset -c gpiochip0 355=0 353=0 328=0 352=0 Fix this by writing back only the bit being cleared, with all other bits set to 1, instead of read-modify-writing the whole register. Since 1-bits are left unchanged by hardware, concurrently-set status bits for other interrupts are preserved.
How do I check if I'm vulnerable to CVE-2026-90124? +
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